Menentukan Alternatif, Kriteria, Bobot dan Sifat - CCTV

Menentukan Alternatif, Kriteria dan Bobot CCTV

Seorang dosen meminta kepada setiap kelompok mahasiswa untuk menganalisa apa saja di lingkungan kerja masing-masing kelompok yang berpotensi terhadap pembuatan sistem pendukung keputusan.

Petunjuk!
A. Mendefinisikan sistem yang dibuat
B. Menentukan landasan teori / metode yang digunakan
C. Hasil dan Pembahasan

A. Definisi Sistem

Sistem Pendukung Keputusan CCTV adalah serangkaian tata cara atau metode memilih cctv dengan memanfaatkan informasi terkait cctv yang didukung oleh algoritma tertentu dan menyediakan output berupa informasi perangkingan, guna memudahkan pengguna dalam mengambil keputusan secara cepat.

B. Landasan Teori

Metode apa yang harus kami gunakan telah ditentukan sebelumnya saat pengundian secara random di ruang kelas, dan kebetulan keberuntungan itu jatuh pada Metode TOPSIS.

C. Hasil dan Pembahasan

Dalam studi kasus ini kami diminta untuk menentukan Alternatif, Kriteria, Sifat dan Bobot, selain itu kami juga harus menyelesaikannya menggunakan metode TOPSIS. Sementara itu, hasil ini kami peroleh dari lingkungan kerja salah satu anggota kelompok kami.

1. Menentukan Alternatif

Seorang konsumen ingin memasang CCTV untuk menunjang sistem keamanan Rukonya. Dia tertarik dengan salah satu brand ternama yaitu Hikvision, tapi Dia masih bingung dan belum bisa menentukan tipe apa yang cocok untuk kebutuhannya itu.

Seorang teknisi bernama Septiyawan merekomendasikan 5 tipe sebagai alternatif pilihan, diantaranya adalah:

1. DS-2CE55A2P, dengan spesifikasi:

• jenis = analog,
• kamera = 1.3 MP,
• implementasi = indoor,
• harga = Rp.450.000,-,
• dimensi = 1/3",
• bentuk = 1/2 lingkaran,
• dukungan DVR = 4CH - WD1
• dukungan kabel = coaxial,
• memori internal = tidak tersedia.

2. DS-2CE15A2P, dengan spesifikasi:

• jenis = analog,
• kamera = 1.3 MP,
• implementasi = outdoor,
• harga = Rp.500.000,-,
• dimensi = 1/3",
• bentuk = oval,
• dukungan DVR = 8CH - WD1
• dukungan kabel = coaxial,
• memori internal = tidak tersedia.

3. DS-2CD2110-I, dengan spesifikasi:

• jenis = IP,
• kamera = 1.3 MP,
• implementasi = outdoor,
• harga = Rp.1.200.000,-,
• dimensi = 1/3",
• bentuk = 1/2 lingkaran,
• dukungan DVR = 16CH - 5MP
• dukungan kabel = coaxial & LAN,
• memori internal = tersedia.

4. DS-2CE56C2T, dengan spesifikasi:

• jenis = HD,
• kamera = 2 MP,
• implementasi = indoor,
• harga = Rp.650.000,-,
• dimensi = 1/3",
• bentuk = 1/2 lingkaran,
• dukungan DVR = 8CH - AHD
• dukungan kabel = coaxial,
• memori internal = tidak tersedia.

5. DS-2CE16C2T, dengan spesifikasi:

• jenis = HD,
• kamera = 2 MP,
• implementasi = outdoor,
• harga = Rp.700.000,-,
• dimensi = 1/3",
• bentuk = oval,
• dukungan DVR = 8CH - AHD
• dukungan kabel = coaxial,
• memori internal = tidak tersedia.

2. Menentukan Kriteria

Terdapat 9 kriteria yang dijadikan acuan dalam pengambilan keputusan, diantaranya adalah:

1. Kesesuaian Jenis

• terdapat 3 jenis CCTV, yaitu analog, IP dan HD,
• klasifikasi poin dibagi menjadi 2, yaitu BAIK = 1 dan BURUK = 0.5,
• jika berjenis IP maka itu BAIK dan selain itu BURUK.

2. Kesesuaian Kamera

• terdapat 2 macam resolusi kamera, yaitu 1.3MP dan 2MP.
• klasifikasi poin dibagi menjadi 2, yaitu BAIK = 1 dan BURUK = 0.5,
• jika beresolusi 2MP maka itu BAIK dan selain itu BURUK.

3. Kesesuaian Tempat

• terdapat 2 macam peruntukan CCTV, yaitu indoor dan outdoor,
• klasifikasi poin dibagi menjadi 2, yaitu BAIK = 1 dan BURUK = 0.5,
• jika outdoor maka itu BAIK dan selain itu BURUK.

4. Kesesuaian Harga

• klasifikasi point dibagi menjadi 2, yaitu BAIK = mengikuti harga sebenarnya dan BURUK = 0,
• jika harga <= Rp.2.000.000,- maka BAIK dan jika harga > Rp.2.000.000,- maka BURUK.

5. Kesesuaian Ukuran

• klasifikasi point dibagi menjadi 2, yaitu BAIK = mengikuti size sebenarnya dan BURUK = 0,
• jika dimensi <= 2” maka BAIK dan jika dimensi > 2” maka BURUK.

6. Kesesuaian Bentuk

• terdapat 2 macam bentuk CCTV, yaitu 1/2 lingkaran dan oval,
• klasifikasi poin dibagi menjadi 2, yaitu BAIK = 1 dan BURUK = 0.5,
• jika berbentuk 1/2 lingkaran maka itu BAIK dan selain itu BURUK.

7. Kesesuaian DVR

• terdapat 4 macam kualitas DVR, yaitu 4CH-WD1, 8CH-WD1, 8CH-AHD, dan 16CH-5MP,
• klasifikasi poin dibagi menjadi 3, yaitu BAIK = 1, CUKUP = 0.5 dan BURUK = 0.1,
• jika 16CH-5MP maka itu BAIK, jika 8CH maka cukup, dan CH dibawah 8 maka BURUK.

8. Kesesuaian Kabel

• terdapat 2 macam yang digunakan, yaitu Coaxial dan LAN,
• klasifikasi poin dibagi menjadi 2, yaitu BAIK = 1 dan BURUK = 0.5,
• jika support keduanya maka itu BAIK dan jika salah satu saja maka itu BURUK.

9. Kesesuaian Memori

Jika tersedia maka BAIK = 1 dan jika tidak tersedia maka BURUK = 0.5.

3. Menentukan Bobot

Tingkat kepentingan setiap kriteria dibobot dalam rentang 1 s/d. 3.

• 1 adalah tidak penting.
• 2 adalah cukup penting.
• 3 adalah sangat penting.

4. Menentukan Sifat

Kriteria	Nama	Bobot	Sifat
C1	Kesesuaian jenis	3	Benefit
C2	Kesesuaian kamera	3	Benefit
C3	Kesesuaian tempat	3	Benefit
C4	Harga CCTV	2	Cost
C5	Ukuran fisik CCTV	2	Cost
C6	Bentuk CCTV	1	Benefit
C7	Dukungna DVR	3	Benefit
C8	Dukungan kabel	3	Benefit
C9	Ketersediaan memori internal	2	Benefit

5. Menentukan Rating Kecocokan

Alternatif	Kriteria
	C1	C2	C3	C4	C5	C6	C7	C8	C9
1	0.5	0.5	0.5	450	1/3	1	0.1	0.5	0.5
2	0.5	0.5	1	500	1/3	0.5	0.5	0.5	0.5
3	1	0.5	1	1200	1/3	1	1	1	1
4	0.5	1	0.5	650	1/3	1	0.5	0.5	0.5
5	0.5	1	1	700	1/3	0.5	0.5	0.5	0.5

6. Menentukan Matriks Keputusan Ternormalisasi

x1	x2	x3	x4	x5	x6	x7	x8	x9
0.5	0.5	0.5	450.000	1/3	1	0.1	0.5	0.5
0.5	0.5	1	500.000	1/3	0.5	0.5	0.5	0.5
1	0.5	1	1200.000	1/3	1	1	1	1
0.5	1	0.5	650.000	1/3	1	0.5	0.5	0.5
0.5	1	1	700.000	1/3	0.5	0.5	0.5	0.5

\[\text{ }\!\!|\!\!\text{ }\!\!|\!\!\text{ x1 }\!\!|\!\!\text{ }\!\!|\!\!\text{ }=\sqrt{\text{(0}\text{.}{{\text{5}}^{\text{2}}}\text{ + 0}\text{.}{{\text{5}}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{+ 0}\text{.}{{\text{5}}^{\text{2}}}\text{+ 0}\text{.}{{\text{5}}^{\text{2}}}\text{) }}\text{= }1.414213562\] r11 = x11 / |x1| = 0.5 / 1.414213562 = 0.353553391
r21 = x21 / |x1| = 0.5 / 1.414213562 = 0.353553391
r31 = x31 / |x1| = 1 / 1.414213562 = 0.707106781
r41 = x41 / |x1| = 0.5 / 1.414213562 = 0.353553391
r51 = x51 / |x1| = 0.5 / 1.414213562 = 0.353553391

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x2  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(0}\text{.}{{\text{5}}^{\text{2}}}\text{ + 0}\text{.}{{\text{5}}^{\text{2}}}\text{ + 0}\text{.}{{\text{5}}^{\text{2}}}\text{+ }{{\text{1}}^{\text{2}}}\text{+ }{{\text{1}}^{\text{2}}}\text{) }}\text{= }1.658312395\] r12 = x12 / |x2| = 0.5 / 1.658312395 = 0.301511345
r22 = x22 / |x2| = 0.5 / 1.658312395 =  0.301511345
r32 = x32 / |x2| = 0.5 / 1.658312395 =  0.301511345
r42 = x42 / |x2| = 1 / 1.658312395 = 0.603022689
r52 = x52 / |x2| = 1 / 1.658312395 = 0.603022689

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x3  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(0}\text{.}{{\text{5}}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{+ 0}\text{.}{{\text{5}}^{\text{2}}}\text{+ }{{\text{1}}^{\text{2}}}\text{) }}\text{= }1.870828693\] r13 = x13 / |x3| = 0.5 / 1.870828693 = 0.267261242
r23 = x23 / |x3| = 1 / 1.870828693 =  0.534522484
r33 = x33 / |x3| = 1 / 1.870828693 =  0.534522484
r43 = x43 / |x3| = 0.5 / 1.870828693 = 0.267261242
r53 = x53 / |x3| = 1 / 1.870828693 = 0.534522484

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x4  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(450}\text{.00}{{\text{0}}^{\text{2}}}\text{ + 500}\text{.00}{{\text{0}}^{\text{2}}}\text{ + 1}\text{.200}\text{.00}{{\text{0}}^{\text{2}}}\text{+ 650}\text{.00}{{\text{0}}^{\text{2}}}\text{+ 700}\text{.00}{{\text{0}}^{\text{2}}}\text{) }}\text{= }1.674.813\] r14 = x14 / |x4| = 450.000 / 1,674,813 = 0.268686645
r24 = x24 / |x4| = 500.000 / 1,674,813 =  0.298540717
r34 = x34 / |x4| = 1.200.000 / 1,674,813 =  0.716497721
r44 = x44 / |x4| = 650.000 / 1,674,813 = 0.388102932
r54 = x54 / |x4| = 700.000 / 1,674,813 = 0.417957004

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x5  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(1/}{{\text{3}}^{\text{2}}}\text{ + 1/}{{\text{3}}^{\text{2}}}\text{ + 1/}{{\text{3}}^{\text{2}}}\text{+ 1/}{{\text{3}}^{\text{2}}}\text{+ 1/}{{\text{3}}^{\text{2}}}\text{) }}\text{= }0.745355992\] r15 = x15 / |x5| = 1/3/ 0.745355992 = 0.447213595
r25 = x25 / |x5| = 1/3/ 0.745355992 =  0.447213595
r35 = x35 / |x5| = 1/3 / 0.745355992 = 0.447213595
r45 = x45 / |x5| = 1/3 / 0.745355992 = 0.447213595
r55 = x55 / |x5| = 1/3 / 0.745355992 = 0.447213595

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x6  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(}{{\text{1}}^{\text{2}}}\text{ + }{{0.5}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{+ }{{\text{1}}^{\text{2}}}\text{+ }{{0.5}^{\text{2}}}\text{) }}\text{= }1.870828693\] r16 = x16 / |x6| = 1 / 1.870828693 = 0.534522484
r26 = x26 / |x6| = 0.5 / 1.870828693 =  0.267261242
r36 = x36 / |x6| = 1 / 1.870828693 = 0.534522484
r46 = x46 / |x6| = 1 / 1.870828693 = 0.534522484
r56 = x56 / |x6| = 0.5 / 1.870828693 = 0.267261242

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x7  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(0}\text{.}{{\text{1}}^{\text{2}}}\text{ + }{{0.5}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{+ 0}\text{.}{{\text{5}}^{\text{2}}}\text{+ }{{0.5}^{\text{2}}}\text{) }}\text{= }1.326649916\] r17 = x17 / |x7| = 0.1 / 1.326649916 = 0.075377836
r27 = x27 / |x7| = 0.5 / 1.326649916 = 0.376889181
r37 = x37 / |x7| = 1 / 1.326649916 = 0.753778361
r47 = x47 / |x7| = 0.5 / 1.326649916 = 0.376889181
r57 = x57 / |x7| = 0.5 / 1.326649916 = 0.376889181

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x8  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(0}\text{.}{{\text{5}}^{\text{2}}}\text{ + }{{0.5}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{+ 0}\text{.}{{\text{5}}^{\text{2}}}\text{+ }{{0.5}^{\text{2}}}\text{) }}\text{= }1.414213562\] r18 = x18 / |x8| = 0.5 / 1.414213562 = 0.353553391
r28 = x28 / |x8| = 0.5 / 1.414213562 = 0.353553391
r38 = x38 / |x8| = 1 / 1.414213562 = 0.707106781
r48 = x48 / |x8| = 0.5 / 1.414213562 = 0.353553391
r58 = x58 / |x8| = 0.5 / 1.414213562 = 0.353553391

\[\text{ }\!\!|\!\!\text{  }\!\!|\!\!\text{  x9  }\!\!|\!\!\text{  }\!\!|\!\!\text{ }=\sqrt{\text{(0}\text{.}{{\text{5}}^{\text{2}}}\text{ + }{{0.5}^{\text{2}}}\text{ + }{{\text{1}}^{\text{2}}}\text{+ 0}\text{.}{{\text{5}}^{\text{2}}}\text{+ }{{0.5}^{\text{2}}}\text{) }}\text{= }1.414213562\] r19 = x19 / |x9| = 0.5 / 1.414213562 = 0.353553391
r29 = x29 / |x9| = 0.5 / 1.414213562 = 0.353553391
r39 = x39 / |x9| = 1 / 1.414213562 = 0.707106781
r49 = x49 / |x9| = 0.5 / 1.414213562 = 0.353553391
r59 = x59 / |x9| = 0.5 / 1.414213562 = 0.353553391

Matriks Ternormalisasi R

0.353553391	0.301511345	0.267261242	0.268686645	0.447213595	0.534522484	0.075377836	0.353553391	0.353553391
0.353553391	0.301511345	0.534522484	0.298540717	0.447213595	0.267261242	0.376889181	0.353553391	0.353553391
0.707106781	0.301511345	0.534522484	0.716497721	0.447213595	0.534522484	0.753778361	0.707106781	0.707106781
0.353553391	0.603022689	0.267261242	0.388102932	0.447213595	0.534522484	0.376889181	0.353553391	0.353553391
0.353553391	0.603022689	0.534522484	0.417957004	0.447213595	0.267261242	0.376889181	0.353553391	0.353553391

7. Perkalian Antara Bobot Dengan Nilai Setiap Atribut

Diperoleh matriks Y sebagai berikut,

0.353553391	0.301511345	0.267261242	0.268686645	0.447213595	0.534522484	0.075377836	0.353553391	0.353553391
0.353553391	0.301511345	0.534522484	0.298540717	0.447213595	0.267261242	0.376889181	0.353553391	0.353553391
0.707106781	0.301511345	0.534522484	0.716497721	0.447213595	0.534522484	0.753778361	0.707106781	0.707106781
0.353553391	0.603022689	0.267261242	0.388102932	0.447213595	0.534522484	0.376889181	0.353553391	0.353553391
0.353553391	0.603022689	0.534522484	0.417957004	0.447213595	0.267261242	0.376889181	0.353553391	0.353553391
*3	*3	*3	*2	*2	*1	*3	*3	*2
Dikali Dengan Bobot

Hasilnya,

1.060660172	0.904534034	0.801783726	0.537373291	0.894427191	0.534522484	0.226133508	1.060660172	0.707106781
1.060660172	0.904534034	1.603567451	0.597081434	0.894427191	0.267261242	1.130667542	1.060660172	0.707106781
2.121320344	0.904534034	1.603567451	1.432995442	0.894427191	0.534522484	2.261335084	2.121320344	1.414213562
1.060660172	1.809068067	0.801783726	0.776205864	0.894427191	0.534522484	1.130667542	1.060660172	0.707106781
1.060660172	1.809068067	1.603567451	0.835914008	0.894427191	0.267261242	1.130667542	1.060660172	0.707106781

8. Menentukan Matriks Solusi Ideal Positif & Negatif 

Nama kriteria	Sifat kriteria	Y+	Y-
C1 = Kesesuaian Jenis	Benefit	Max= 2.121320344	Min= 1.060660172
C2 = Kesesuaian Kamera	Benefit	Max= 1.809068067	Min= 0.904534034
C3 = Kesesuaian Tempat	Benefit	Max= 1.603567451	Min= 0.801783726
C4 = Harga CCTV	Cost	Min= 0.537373291	Max= 1.432995442
C5 = Ukuran fisik CCTV	Cost	Min= 0.894427191	Max= 0.894427191
C6 = Bentuk CCTV	Benefit	Max= 0.534522484	Min= 0.267261242
C7 = Dukungna DVR	Benefit	Max= 2.261335084	Min= 0.226133508
C8 = Dukungan kabel	Benefit	Max= 2.121320344	Min= 1.060660172
C9 = memori internal	Benefit	Max= 1.414213562	Min= 0.707106781
Dapat disimpulkan :		A+ = { 2.121320344; 1.809068067; 1.603567451; 0.537373291; 0.894427191; 0.534522484; 2.261335084; 2.121320344; 1.414213562;}	A- = { 1.060660172; 0.904534034; 0.801783726; 1.432995442; 0.894427191; 0.267261242; 0.226133508; 1.060660172; 0.707106781;}

9.a Jarak Antara Alternatif Ai Dengan Solusi Ideal Positif 

\[D{{1}^{+}}=\sqrt{\begin{smallmatrix}
 {{\text{(1}\text{.060660172-2}\text{.121320344)}}^{\text{2}}}\text{+(0}\text{.904534034-1}\text{.809068067}{{\text{)}}^{\text{2}}}\text{+(0}\text{.801783726-1}\text{.603567451}{{\text{)}}^{\text{2}}} \\
 \text{+(0}\text{.537373291-0}\text{.537373291}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.534522484-0}\text{.534522484}{{\text{)}}^{\text{2}}}
 \\
 \text{+(0}\text{.226133508-2}\text{.261335084}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-2}\text{.121320344}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-1}\text{.414213562}{{\text{)}}^{\text{2}}}
\end{smallmatrix}}=2.890170309\]
\[D{{2}^{+}}=\sqrt{\begin{smallmatrix}
 {{\text{(1}\text{.060660172-2}\text{.121320344)}}^{\text{2}}}\text{+(0}\text{.904534034-1}\text{.809068067}{{\text{)}}^{\text{2}}}\text{+(1}\text{.603567451-1}\text{.603567451}{{\text{)}}^{\text{2}}} \\
 \text{+(0}\text{.597081434-0}\text{.537373291}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.267261242-0}\text{.534522484}{{\text{)}}^{\text{2}}}
 \\
 \text{+(1}\text{.130667542-2}\text{.261335084}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-2}\text{.121320344}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-1}\text{.414213562}{{\text{)}}^{\text{2}}}
\end{smallmatrix}}=2.218464456\]
\[D{{3}^{+}}=\sqrt{\begin{smallmatrix}
 {{\text{(2}\text{.121320344-2}\text{.121320344)}}^{\text{2}}}\text{+(0}\text{.904534034-1}\text{.809068067}{{\text{)}}^{\text{2}}}\text{+(1}\text{.603567451-1}\text{.603567451}{{\text{)}}^{\text{2}}} \\
 \text{+(1}\text{.432995442-0}\text{.537373291}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.534522484-0}\text{.534522484}{{\text{)}}^{\text{2}}}
 \\
 \text{+(2}\text{.261335084-2}\text{.261335084}{{\text{)}}^{\text{2}}}\text{+(2}\text{.121320344-2}\text{.121320344}{{\text{)}}^{\text{2}}}\text{+(1}\text{.414213562-1}\text{.414213562}{{\text{)}}^{\text{2}}}
\end{smallmatrix}}=1.272918244\]
\[D{{4}^{+}}=\sqrt{\begin{smallmatrix}
 {{\text{(1}\text{.060660172-2}\text{.121320344)}}^{\text{2}}}\text{+(1}\text{.809068067-1}\text{.809068067}{{\text{)}}^{\text{2}}}\text{+(0}\text{.801783726-1}\text{.603567451}{{\text{)}}^{\text{2}}} \\
 \text{+(0}\text{.776205864-0}\text{.537373291}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.534522484-0}\text{.534522484}{{\text{)}}^{\text{2}}}
 \\
 \text{+(1}\text{.130667542-2}\text{.261335084}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-2}\text{.121320344}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-1}\text{.414213562}{{\text{)}}^{\text{2}}}
\end{smallmatrix}}=2.174467114\]
\[D{{5}^{+}}=\sqrt{\begin{smallmatrix}
 {{\text{(1}\text{.060660172-2}\text{.121320344)}}^{\text{2}}}\text{+(1}\text{.809068067-1}\text{.809068067}{{\text{)}}^{\text{2}}}\text{+(1}\text{.603567451-1}\text{.603567451}{{\text{)}}^{\text{2}}} \\
 \text{+(0}\text{.835914008-0}\text{.537373291}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.267261242-0}\text{.534522484}{{\text{)}}^{\text{2}}}
 \\
 \text{+(1}\text{.130667542-2}\text{.261335084}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-2}\text{.121320344}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-1}\text{.414213562}{{\text{)}}^{\text{2}}}
\end{smallmatrix}}=2.046695928\]

9.b Jarak Antara Alternatif Ai Dengan Solusi Ideal Negatif

\[D{{1}^{-}}=\sqrt{\begin{smallmatrix} {{\text{(1}\text{.060660172-1}\text{.060660172)}}^{\text{2}}}\text{+(0}\text{.904534034-0}\text{.904534034}{{\text{)}}^{\text{2}}}\text{+(0}\text{.801783726-0}\text{.801783726}{{\text{)}}^{\text{2}}} \\ \text{+(0}\text{.537373291-1}\text{.432995442}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.534522484-0}\text{.267261242}{{\text{)}}^{\text{2}}} \\ \text{+(0}\text{.226133508-0}\text{.226133508}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-1}\text{.060660172}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-0}\text{.707106781}{{\text{)}}^{\text{2}}} \end{smallmatrix}}=0.934648388\] \[D{{2}^{-}}=\sqrt{\begin{smallmatrix} {{\text{(1}\text{.060660172-1}\text{.060660172)}}^{\text{2}}}\text{+(0}\text{.904534034-0}\text{.904534034}{{\text{)}}^{\text{2}}}\text{+(1}\text{.603567451-0}\text{.801783726}{{\text{)}}^{\text{2}}} \\ \text{+(0}\text{.597081434-1}\text{.432995442}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.267261242-0}\text{.267261242}{{\text{)}}^{\text{2}}} \\ \text{+(1}\text{.130667542-0}\text{.226133508}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-1}\text{.060660172}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-0}\text{.707106781}{{\text{)}}^{\text{2}}} \end{smallmatrix}}=1.469622805\] \[D{{3}^{-}}=\sqrt{\begin{smallmatrix} {{\text{(2}\text{.121320344-1}\text{.060660172)}}^{\text{2}}}\text{+(0}\text{.904534034-0}\text{.904534034}{{\text{)}}^{\text{2}}}\text{+(1}\text{.603567451-0}\text{.801783726}{{\text{)}}^{\text{2}}} \\ \text{+(1}\text{.432995442-1}\text{.432995442}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.534522484-0}\text{.267261242}{{\text{)}}^{\text{2}}} \\ \text{+(2}\text{.261335084-0}\text{.226133508}{{\text{)}}^{\text{2}}}\text{+(2}\text{.121320344-1}\text{.060660172}{{\text{)}}^{\text{2}}}\text{+(1}\text{.414213562-0}\text{.707106781}{{\text{)}}^{\text{2}}} \end{smallmatrix}}=2.757957790\] \[D{{4}^{-}}=\sqrt{\begin{smallmatrix} {{\text{(1}\text{.060660172-1}\text{.060660172)}}^{\text{2}}}\text{+(1}\text{.809068067-0}\text{.904534034}{{\text{)}}^{\text{2}}}\text{+(0}\text{.801783726-0}\text{.801783726}{{\text{)}}^{\text{2}}} \\ \text{+(0}\text{.776205864-1}\text{.432995442}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.534522484-0}\text{.267261242}{{\text{)}}^{\text{2}}} \\ \text{+(1}\text{.130667542-0}\text{.226133508}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-1}\text{.060660172}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-0}\text{.707106781}{{\text{)}}^{\text{2}}} \end{smallmatrix}}=1.462588376\] \[D{{5}^{-}}=\sqrt{\begin{smallmatrix} {{\text{(1}\text{.060660172-1}\text{.060660172)}}^{\text{2}}}\text{+(1}\text{.809068067-0}\text{.904534034}{{\text{)}}^{\text{2}}}\text{+(1}\text{.603567451-0}\text{.801783726}{{\text{)}}^{\text{2}}} \\ \text{+(0}\text{.835914008-1}\text{.432995442}{{\text{)}}^{\text{2}}}\text{+(0}\text{.894427191-0}\text{.894427191}{{\text{)}}^{\text{2}}}\text{+(0}\text{.267261242-0}\text{.267261242}{{\text{)}}^{\text{2}}} \\ \text{+(1}\text{.130667542-0}\text{.226133508}{{\text{)}}^{\text{2}}}\text{+(1}\text{.060660172-1}\text{.060660172}{{\text{)}}^{\text{2}}}\text{+(0}\text{.707106781-0}\text{.707106781}{{\text{)}}^{\text{2}}} \end{smallmatrix}}=1.623492229\]

10. Menentukan Nilai Preferensi Untuk Setiap Alternatif

\[V1=\frac{D_{1}^{-}}{D_{1}^{-}+D_{1}^{+}}=\frac{0.934648388}{0.934648388+2.890170309}=0.244364102\] \[V2=\frac{D_{2}^{-}}{D_{2}^{-}+D_{2}^{+}}=\frac{1.469622805}{1.469622805+2.218464456}=0.398478317\] \[V3=\frac{D_{3}^{-}}{D_{3}^{-}+D_{3}^{+}}=\frac{2.757957790}{2.757957790+1.272918244}=0.684208040\] \[V4=\frac{D_{4}^{-}}{D_{4}^{-}+D_{4}^{+}}=\frac{1.462588376}{1.462588376+2.174467114}=0.402135293\] \[V5=\frac{D_{5}^{-}}{D_{5}^{-}+D_{5}^{+}}=\frac{1.623492229}{1.623492229+2.046695928}=0.442345776\]

11. Perangkingan

Altenatif	Ranking
DS-2CE55A2P	5
DS-2CE15A2P	4
DS-2CD2110-I	1
DS-2CE56C2T	3
DS-2CE16C2T	2